go solution
@Absinthe Keeping in the tradition of choosing the worst possible languages for #toyprogrammingchallenge this time it's Go: https://gitlab.com/tymorl/warmups/blob/master/commonListSuffix/sol.go . The algorithm is essentially the same as @khird proposed.
@Absinthe I'm very slowly working on a little clever one, and I'm going to use it to make me a new profile picture, just you wait...
@Absinthe couldn't resist this one:
https://git.sr.ht/~namark/snail/tree/master/snail.cpp
I swear I tried to do it for square only but it seems to work for rectangles too.
In true c++ fashion it comes with a bunch of illegible library code, which I had to extend with a couple of extra abominable appendages to accommodate this toy.
Okay, here is one before the weekend.
Conway's Game of Life. It is a simple concept. Set up some cool patterns and let it run on a good cycle. I just did it, using '*' and ' ' but feel free to do it graphically if you prefer. Here are the rules, and my code is in the same repo so let that be a spoiler warning:
https://git.qoto.org/Absinthe/life-conway/blob/master/README.md
@Absinthe Hello! I saw you write about programming puzzles (and that's why I followed you), I was wondering if you know Advent of Code, and if you do, how do you like it 🙂
https://www.adventofcode.com
Belatedly, a Balanced Brackets tester, in Python:
https://raw.githubusercontent.com/patchcali/toy-programs-gpl/master/test_brackets_balanced.py
The number and nature of the compromises I have to make when choosing a programming language for every goddamn project really gets to me
Except for C. To every use-case which C is suitable, it has never been a disappointment to me.
Python Solution
def snail_sort(matrix):
new_list = []
while matrix:
new_list.extend(matrix.pop(0))
if not matrix:
continue
for i in range(len(matrix)):
new_list.append(matrix[i].pop())
if not matrix:
break
if not matrix:
continue
new_list.extend(reversed(matrix.pop()))
if not matrix:
continue
for i in range(len(matrix) - 1, -1, -1):
new_list.append(matrix[i].pop(0))
if not matrix:
break
return new_list
MATRIX = [
[1, 2, 3, 4, 5],
[16, 17, 18, 19, 6],
[15, 24, 25, 20, 7],
[14, 23, 22, 21, 8],
[13, 12, 11, 10, 9],
]
snail_sort(MATRIX)
I borrowed this one from codewars
Snail Sort
Given an n x n array, return the array elements arranged from outermost elements to the middle element, traveling clockwise.
array = [[1,2,3],
[4,5,6],
[7,8,9]]
snail(array) #=> [1,2,3,6,9,8,7,4,5]
For better understanding, please follow the numbers of the next array consecutively:
array = [[1,2,3],
[8,9,4],
[7,6,5]]
snail(array) #=> [1,2,3,4,5,6,7,8,9]
This image will illustrate things more clearly:
NOTE: The idea is not sort the elements from the lowest value to the highest; the idea is to traverse the 2-d array in a clockwise snailshell pattern.
Octave solution
function sorted = snail(array)
if numel(array) <= 1
sorted = array;
else
sorted = [array(1, 1:(end-1)),...
array(1:(end-1), end)',...
array(end, end:-1:2),...
array(end:-1:2, 1)',...
snail(array(2:(end-1), 2:(end-1))) ]; end; end;
For those of you who missed the announcement from the @freemo account just wanted to reiterate it here.
In honor of our new Indian friends we added two new emoji to the server.
Also if anyone has any emoji they want added, even if its just for personal use (like a monogram of your name or a picture of your own face, anything) we can add it. Just send a 50kb or less PNG image to @freemo and it can be added.
I borrowed this one from codewars
Snail Sort
Given an n x n array, return the array elements arranged from outermost elements to the middle element, traveling clockwise.
array = [[1,2,3],
[4,5,6],
[7,8,9]]
snail(array) #=> [1,2,3,6,9,8,7,4,5]
For better understanding, please follow the numbers of the next array consecutively:
array = [[1,2,3],
[8,9,4],
[7,6,5]]
snail(array) #=> [1,2,3,4,5,6,7,8,9]
This image will illustrate things more clearly:
NOTE: The idea is not sort the elements from the lowest value to the highest; the idea is to traverse the 2-d array in a clockwise snailshell pattern.
@Absinthe I am learning about it and want to shift my career to business analytics. Right now, I am working as sports analyst.
@Absinthe where are the data science people? Any idea?
Here's a freebie!
This problem was asked by Google.
Given a list of integers S and a target number k, write a function that returns a subset of S that adds up to k. If such a subset cannot be made, then return null.
Integers can appear more than once in the list. You may assume all numbers in the list are positive.
For example, given S = [12, 1, 61, 5, 9, 2] and k = 24, return [12, 9, 2, 1] since it sums up to 24.
The green faerie