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I just completed "The Treachery of Whales" - Day 7 - Advent of Code 2021 adventofcode.com/2021/day/7

Okay, here is the challenge for this week.

Tennis is a cool sport to watch. Especially, if either Serena or Venus or both are playing. :) However, the scoring is really odd, because it is based on the clock face. To make it even more fun, it did come from France, so instead of Zero we refer to l'œuf or "the egg". However, as we now pronounce it , it is "love". I am certain that there can be some interesting jokes in there, but I am not going for any of them. :)

Anyway, when you begin a game both players have scored zero times so their score is said to be "love - love" or "love all". When a player has scored 1 time, they are said to have "15" as advancing around the clock face 1/4 of the way. Their second score would be called "30" since that would be 1/2 way around. Obviously, their third score should be "40" because that forces you to win by 2 :) Not sure it makes sense, but that is how it works. So as an example a game might go like this:

love - love
15 - love
30 - love
40 - love
Game - player1

Not all games work out that one player gets to run the score, so it could also go like this:
love - love
15 - love
15 - 15
15 - 30
30 - 30
30 - 40
Game - player2

However, after the 3rd point is scored if both players have 40 the score is said as
"Deuce"
Because, France. :)

At any point when a player becomes 2 points ahead after 40 they win, and we say Game - <player name>
But after the score is tied at 40 or higher, the next point is called "advantage" so we no longer care about the underlying clock face scores, and merely go through "Deuce", "Advantage - player1" "Deuce" "Advantage - player2" "Game - player2". In theory, one could continually bounce from "Deuce" to advantage one player or the other until one of them players simply falls out or dies. Though I am not aware of that ever actually happening. There have been some pretty long games.

"Back in 1975 on May 26, at the Surrey Grass Court Championships at Surbiton, Anthony Fawcett and Keith Glass racked up a record 37 deuces in a single game for a grand total of 80 points."

But I digress. Here is your challenge if you choose to accept it.

Write a method/function that takes any legal tennis game score, such as (0, 0) or (5,3) and so on, and have it output the traditional tennis score as described above, "love - love" or "Game - player1" in my example of legal scores. Keep in mind, (12, 2) is not a legal score, as once the first player achieved 4 he would have already won. You don't need to test for this, but be aware it is not a scenario you should have to deal with. You can represent any tie up to 2 simply as 'love - love' or '15 - 15' or '30 - 30' but starting at 3 you would not say '40 - 40' but rather "Deuce" at that level and any higher. If you would like to do so, as a bonus you could represent the simple ties less than 3:3 (Deuce) with the 'all' so 'love all', '15 all', or '30 all' would be a bonus representation, but '40 all' would be incorrect, as it should merely be 'Deuce'.

Use whatever language or methods you like. I am using Java. I will also have unit tests. You are free not to use them, but I am not interested in testing anyone's code for accuracy, so if you don't provide them, the best you can hope for is "Nice job. Good effort. I guess." At least from me :)
Try to focus on good quality code. Also focus on reduction of complexity, DRY, and certainly use subroutines as necessary.

Good Luck!!

I will probably be checking mine in to my GitHub or GitLab repo at some point later in the week.

@Absinthe Ha, but you saw it along with a lengthy post that starts with a paragraph about that chart being a complete lie.

Here should be a simple one. It was fun to do in Java and with chained calls it turns out to be somewhat of a one-liner. This is not a code-golf thing, but feel free to try it that way if that is your interest.

"Square Odd"
Let's process an integer. The idea is that if the number contains odd digits they need to be converted to their squared value. Even digits are passed through unchanged.

For example, given the number 232, you would output 292. Or in the case of 99, you would output 8181. But if it were 22 then the output would be 22.

If this is too simple and you would like a bit more of a challenge see if you can try a couple bonus situations.

1*. determine if a number is already in this state. For example 232 wouldn't be because 3 is not squared. However, 212 could be, as could 2814 since that could have come from 294.

and
2*. given a number possibly in this state already, decode it back to the original number.

Since 1 squared is 1 and some squares have even digits like 81 such a number could have started out as '9' or actually '81'. So in 1 and 2 you may want to come up with multiple initial beginnings. So given such '81' the answer would be both of those '81' and '9'.

Things in my life have changed. I am now in a much larger focus on Java. I am still a huge fan of TDD and Test First, but I guess that is a religious thing so I will try to contain my zeal.

Initially the challenges were intended as small problems that should be in the 1-3 hour at most. As well, I focused towards Python and the problems I was using to learn the particular concepts I was working on at the time. Since my shift to Java I am less interested in some of the finer concepts and more interested in general issues. So even though I might find a solution that uses a whole pile of chained references interesting, its solution in some other language may not be nearly as interesting to you :)

I will try to be better about posting more often. Unless I find people aren't interested, in which case I won't waste the bandwidth :)

Tried a today, was pretty fun. @namark thanks for recommending these! I expect I’m gonna spend a lot of hours on these in the next few weeks.

I just boosted the last that I had posted from over a year ago.

I still think this is an interesting problem to solve. I have yet to attack it myself, but am definitely considering it. I have recently been doing a bunch more smaller exercises, and perhaps can post a few of those. Though I haven't necessarily written them, I have found them fun to do.

I do have some ideas, but for now I am waiting to see if anyone is even still interested in the puzzles anyway.

Okay, here's one with a story :) Let's see if this is entertaining enough :D

Here is a problem that involves being jerk.

You receive a parking ticket and decide to pay in the least
convient way possible... change. This decision comes to mind
because the tickets are in strange amounts because they use
the cents portion for some kind of internal encoding.

You decide to pay all in pennies but when you start to collect
them someone informs you that although change will be accepted,
if the counts of coins exceed the quantities required for a wrapper
then you must roll them.

US Coinage count to a roll
0.01 = 50
0.05 = 40
0.10 = 50
0.25 = 40
0.50 = 20
$1.00 = 25 (small) or 20 (large)

Question 1.
How many rolls and free coins of each can you provide to pay your
$100.37 ticket in order to use the highest count of unrolled coins?

Considering that a ticket can cost anywhere from $1.00 to $250.00.
You start telling everyone else about your plan and they decide to
play too, so you calculate how they should pay as well.

For example, 45 pennies 21 nickles for a $1.00 ticket might be
pretty obnoxious :).

Question 2. Which fine amount (in that range) would allow you to
provide the highest number of unrolled coins?

Question 3. The parking authority figures out what you are doing
and decides to change things up by hiring you. Your job is to
determine the best fine values to get paid in the least amount of
unrolled coins. What are those amounts what are those amounts (still
within that range of $1.00 to $250.00)

Just to clean it up a little, and add some more entertainment.

Okay, here's one with a story :) Let's see if this is entertaining enough :D

Here is a problem that involves being jerk.

You receive a parking ticket and decide to pay in the least
convient way possible... change. This decision comes to mind
because the tickets are in strange amounts because they use
the cents portion for some kind of internal encoding.

You decide to pay all in pennies but when you start to collect
them someone informs you that although change will be accepted,
if the counts of coins exceed the quantities required for a wrapper
then you must roll them. You also figure out that collecting all
these coins is a bit of a nuisance for you. So your goal is to
reduce the overall number of coin rolls while maximizing the
number of free (or unrolled individual coins).

US Coinage count to a roll
0.01 = 50
0.05 = 40
0.10 = 50
0.25 = 40
0.50 = 20
$1.00 = 25 (small) or 20 (large)

Question 1.
How many rolls and free coins of each can you provide to pay your
$100.37 ticket in order to use the highest count of unrolled coins
while using the least number of rolled coins?

Considering that a ticket can cost anywhere from $1.00 to $250.00.
You start telling everyone else about your plan and they decide to
play too, so you calculate how they should pay as well.

To make things a little more interesting, you show up at a city council
meeting and propose that because of the time involved in processing
unrolled coinage that the parking authority should, rather than
bother with unrolled coins, all unrolled coins they collect should
just be donated to the city coucil's general fund. They pass this
unanimously.

For example, 45 pennies 21 nickles for a $1.00 ticket might be
pretty obnoxious :).

Question 2. Which fine amount (in that range) would allow you to
provide the highest number of unrolled coins?

Question 3. The parking authority figures out what you are doing
and decides to change things up by hiring you. Your job is to
determine the best fine values to get paid in the least amount of
unrolled coins. What are those amounts what are those amounts (still
within that range of $1.00 to $250.00)

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