Show more

@codepuppy CO2 is absurdly stable, which is why it's a combustion product and why Venus is full of it.

Each C=O bond in a CO2 molecule has a bond enthalpy of 804.4 kJ/mol. That works out to 8.342 eV so photodissociation would need a photon with λ > 148.63 nm. That's scary far UV.

A krypton excimer laser (146 nm) could break it, but a good catalyst would be far more efficient. :)

Qoto Mastodon

QOTO: Question Others to Teach Ourselves
An inclusive, Academic Freedom, instance
All cultures welcome.
Hate speech and harassment strictly forbidden.