@margraf Assume the bowl is approximately a truncated cone and the upper radius is R. The base radius looks about 70% of the upper radius and the height looks about 90% of the upper radius. Thus the volume of the bowl is about π/3*0.9R*(R^2+(0.7R)^2+R*0,7R)≈2.06R^3. The pearls seem to have a diameter about R/20, thus a volume of π/6*(R/20)^3=πR^3/48000. So that gives about 31500 pearls.