\[\int\frac{\mathrm{d}^dk}{(2\pi)^d}\frac{k^{2a}}{(k^2-\Delta)^b}=\mathrm{i}(-1)^{a-b}\frac{1}{(4\pi)^{d/2}}\frac{1}{\Delta^{b-a-\frac{d}{2}}}\frac{\Gamma(a+\frac{d}{2})\Gamma(b-a-\frac{d}{2})}{\Gamma(b)\Gamma(\frac{d}{2})}\]
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