here, have an echo
#include <stdio.h>
int main(int argc, char **argv)
{
for(char *s;(s = *(++argv))!=0;) printf("%s ", s);
puts("\b");
}
@ivesen@miniwa.moe
@Absinthe nah, I checked. argv[argc] is always null, and argc is at least 1.
@ivesen argc will be 1 to account for argv[0]. argv[argc] likewise should always be NULL or actually out of bounds depending on the compiler implementation since the last thing on the CMD line will be argv[argc-1]...
@Absinthe
chapter 5.1.2.2.1 defines argv[argv] explicitly as being null.
the only case this doesn't hold for is if argv you don't have a program name, at which point you're not working with an operating system any more
http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf
chapter 5.1.2.2.1 defines argv[argv] explicitly as being null.
the only case this doesn't hold for is if argv you don't have a program name, at which point you're not working with an operating system any more
http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf
@ivesen okay, I'll give you that. But, not really my business anyway, you didn't ask for review. Occupational hazard. Forget I said anything.
