Control.Applicative.QQ.ADo in #haskell is
Control.Applicative.QQ.ADo
Correct Answer Show more
@brokenix the answer is in the first line of the documentation, "Pointful version of Language.Haskell.Meta.QQ.Idiom."
re: Correct Answer Show more
@antares :D i should have started the post with note to self
QOTO: Question Others to Teach Ourselves An inclusive, Academic Freedom, instance All cultures welcome. Hate speech and harassment strictly forbidden.
re: Correct Answer
@antares :D i should have started the post with note to self