I borrowed this one from codewars

Snail Sort
Given an n x n array, return the array elements arranged from outermost elements to the middle element, traveling clockwise.

array = [[1,2,3],
snail(array) #=> [1,2,3,6,9,8,7,4,5]
For better understanding, please follow the numbers of the next array consecutively:

array = [[1,2,3],
snail(array) #=> [1,2,3,4,5,6,7,8,9]
This image will illustrate things more clearly:

NOTE: The idea is not sort the elements from the lowest value to the highest; the idea is to traverse the 2-d array in a clockwise snailshell pattern.

Octave solution 


function sorted = snail(array)
if numel(array) <= 1
sorted = array;
sorted = [array(1, 1:(end-1)),...
array(1:(end-1), end)',...
array(end, end:-1:2),...
array(end:-1:2, 1)',...
snail(array(2:(end-1), 2:(end-1))) ]; end; end;


Octave solution 

@khird looks good, much better than my python solution :)

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