La Fée Verte @Absinthe@qoto.org

@freemo @Absinthe some people (eg. those on the autism spectrum) are uncomfortable with direct eye contact

eg. i for one can handle it in images but not irl. for some it's more intense.

so it's best to be safe an CW eye contact

@Absinthe

Belatedly, a Balanced Brackets tester, in Python:

https://raw.githubusercontent.com/patchcali/toy-programs-gpl/master/test_brackets_balanced.py

#toyprogrammingchallenge

The number and nature of the compromises I have to make when choosing a programming language for every goddamn project really gets to me

Except for C. To every use-case which C is suitable, it has never been a disappointment to me.

#toyprogrammingchallenge

I borrowed this one from codewars

Snail Sort
Given an n x n array, return the array elements arranged from outermost elements to the middle element, traveling clockwise.

array = [[1,2,3],
[4,5,6],
[7,8,9]]
snail(array) #=> [1,2,3,6,9,8,7,4,5]
For better understanding, please follow the numbers of the next array consecutively:

array = [[1,2,3],
[8,9,4],
[7,6,5]]
snail(array) #=> [1,2,3,4,5,6,7,8,9]
This image will illustrate things more clearly:

NOTE: The idea is not sort the elements from the lowest value to the highest; the idea is to traverse the 2-d array in a clockwise snailshell pattern.

@Absinthe

function sorted = snail(array)
if numel(array) <= 1
sorted = array;
else
sorted = [array(1, 1:(end-1)),...
array(1:(end-1), end)',...
array(end, end:-1:2),...
array(end:-1:2, 1)',...
snail(array(2:(end-1), 2:(end-1))) ]; end; end;

For those of you who missed the announcement from the @freemo account just wanted to reiterate it here.

In honor of our new Indian friends we added two new emoji to the server.

Also if anyone has any emoji they want added, even if its just for personal use (like a monogram of your name or a picture of your own face, anything) we can add it. Just send a 50kb or less PNG image to @freemo and it can be added.

@stateastic

Hi there, Freemo's my name, Data Science my game :) How can I help :)

@Absinthe

@Absinthe I am learning about it and want to shift my career to business analytics. Right now, I am working as sports analyst.

@Absinthe where are the data science people? Any idea?

Here's a #toyprogrammingchallenge requiring a bit of algebra.

For any four non-collinear points A, B, C, and D in three-dimensional space, there is a unique hyperbolic paraboloid H containing the lines AB, BC, CD, and AD (that is, every point on any of these lines is also on the surface of H). Write a program that accepts Cartesian coordinate triplets representing A, B, C, and D and prints an equation in x, y, and z that is satisfied if and only if <x, y, z> is a point on H.

Your program's output may differ from the examples but should be optimised for human readability. Combine like terms, omit terms equal to zero and avoid unnecessary factors (e.g. prefer "x = y" to "2x + 0 = 4y - 2y" even though both describe the same surface).

Example 1 input:
<0, 1, -1>; <1, 0, 1>; <0, -1, -1>; <-1, 0, 1>
Example 1 output:
z = x² - y²

Example 2 input:
<1, 1, 1>; <1, 0, -1>; <-1, 1, -1>; <-1, 0, 1>
Example 2 output:
2y = xz + 1

Example 3 input:
<0, 1, 1>; <0, 1, -1>; <0, -1, -1>; <0, -1, 1>
Example 3 output:
x = 0

@Absinthe

Pretty straightforward. Might be possible to improve on the factorial one by counting factors, because computers can generally calculate x^n faster than just multiplying it out, so if you figure out that the answer would be 2^a * 3^b * 5^c... it could outpace the naive 1 * 2 * 3 * ... * n method.

That said, I tried such an approach and while it does scale better than linear, the upfront cost is high enough that the breakeven point is way past anything my computer can represent in floating point. So for practical use, this is what I'd put forward.

function term = fibonacci(index)
root = sqrt(5);
term = (((1 + root)/2).^index - ((1 - root)/2).^index) ./ root; end;

function number = factorial(argument)
number = ones(size(argument));
for factor = 1:max(argument)
number(argument >= factor) *= factor; end; end;

Still trying to find a style i like for the double L... Thoughts on this one?

#calligraphy #handwriting #writing #copperplate