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@Pat
Its multiple choice so no reason it would add up to 100%

Just a reminder **all** American cops are bad people. That is all.

Another 3 attempt win, 2 days in a row. Im pretty good at this ;)

Wordle 215 3/6

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@mishathings I dont know about that software but its probably "mishathings"

@khird Yea I agree the sequential case for 5 is impossible.. the key is that you need to maneuver into a state where only the last step you can select all of the same oriented coins in a garunteed way. That cant happen in any arrangements. So yea I agree with yoru analysis here.

@khird hmm.. there is also the case where you can flip some number of coins but it doesnt have to be the coins you revealed (if you flip a coin not revealed you dont get to know the new or old state)... but that might be too easy

@khird

Never mind, i take that back too (I have a cold and clearly im not thinking straight :) )

@jronkain I mean, he said there are no investors, and then you asked about becoming an investor. He probably thought you were trolling.

So thinking about this some more, I thibnk my approach actually does work. **But** only for the easier case where the selections are allowed to be made sequentially rather than simultaneously.

I ran through the 5 case select 3 example and can solve it using sequential selection but impossible with simultaneous selection

@khird

Unless we are talking about famous people like Elon musk (and I dont listen to them) I wouldnt say this is accurate. Your average schmuck who is investing doesnt have enough influence or perceive himself as having enough influence for that to be his motivation. People dont generally think in those terms when they might effect 0.0000001% of a market with their opinions.

@mushambo

hmm yes you may be right, this is why i should have worked through some examples first... well at least i got a notation to start with.

@khird

I think thats a pretty natural expression though. People are going to get excited and shout from the roof tops when they are winning. Less motivation to tell everyone when you loose. I dont see that pattern as a scam so much as just not being reliable to gauge the market, but then again neither is it accurate to gauge the stock market off of what people brag they made either.

I can say this, I've lost money when crypto went down, gained when it went up. I am usually smart to get in and get out of crypto at the right times to optimize my profits. With that said I have made an absolute fortune off crypto investments, far more than I would ever need to live off of.

@mushambo

@freemo some further observations:

For any number of boxes:
If you're allowed to choose all the boxes, a win is trivially possible: flip all to heads.
If you're allowed to choose all but one of the boxes, a win is trivially possible: flip all to heads; if you then see a tails turn it to heads, if not turn all coins to tails.

For five boxes:
There's no solution with three choices, because there's no penultimate state from which you can guarantee that you'll choose all the remaining heads or all the remaining tails. So five boxes has only the trivial solutions.

For six boxes:
I have a solution for four choices in five moves, which may not be optimal (I haven't searched exhaustively for other strategies).

The number of patterns for given numbers of boxes and choices is from the OEIS: oeis.org/A047996, under "example". I don't understand the notation they use for the generating formula, but they call it a "circular binomial coefficient" which makes sense.

@khird I actually created a notation/process where you can determine if a configuration is solvable. I didnt have a chance to try it out on various combos. Works like this.

Represent selection modes with binary numbers. So selecting one out of 4 boxes might look like 0001, 2 selected out of 4 would be 0011 or 0101.

To see if two selection modes are equivalent reduce them to what im calling "standard form". What that means is you left or right shift the binary number (taking any digits that roll off and replacing it on the other end) and do this until the number is in its smallest representation. So 1010 would have a standard form of 0101 (most significant digits on the left). If the standard form of two selection modes are the same then they are equivelant.

Next compute all possible selection modes in standard form for the given parameters. For the original puzzle this would be:

0011
0101

No other selection modes are possible.

Next do an OR operation on all possible selection modes, here we get:

0111

If the resulting binary number has one or fewer 0s then a solution is possible. If it has greater then a solution is impossible.

@groovestomp We might need to add a new category for you: Ultrawhelmed

How whelmed are you today?

Which type of dementia do you think has?

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